Endurance swimmer Colin Macleod will be swimming the first strokes of the Big Minch Swim soon after 3am tomorrow morning (Monday June 10th) – hoping to become the first man to conquer the Big Minch.

The Big Minch Swim 2019 starts from Gairloch on the west coast of the mainland, heading, in as straight a line as Colin can manage, for Lemreway in Lochs, a total distance of 25 miles.

He’ll be supported on the route by support boat the Endeavour, skippered by Donald ‘DK’ MacDonald, with son Joseph Macleod on board, in charge of nutrition, and kayakers Brian Wilson and Robert Emmott on the water, to monitor Colin’s condition and pass information directly to him in the water.

The swim will raise funds for Cancer Research UK, with his target of £5,000 already 75% towards completion on his JustGiving page. (https://www.justgiving.com/fundraising/theminchswims)

Originally, Colin planned to swim alongside Harris athlete Paul Finnegan on his own solo attempt – the pair completed the 15-mile Little Minch swim together in June 2018, from the Isle of Skye to Harris. Sadly, a chest infection earlier this year knocked Paul’s training schedule back, though he still plans to make the attempt with his own support crew later this summer.

Colin was part of a three-person team who set out to conquer the Minch in 2018, with his team-mate Colleen Blair becoming the first person to swim the Minch solo at the end of the effort.

That attempt ended in drama for Colin, who was swimming strongly within a couple of miles of his destination when he was pulled from the water by MV Loch Seaforth’s fast rescue boat. The team support boat had lost sight of him in darkness and called emergency services, believing him to be in trouble.

You can follow this new challenge using Colin’s live tracker at https://share.findmespot.com/shared/faces/viewspots.jsp?glId=0PVafKO6mn9C3ydojszrfu5uZjGtkcy2z

Pictures show Colin powering through the water during an earlier challenge in 2018 (Noel Hawkins) and with wife and supporter-in-chief Donna (Colin Macleod).